Answer:

To find out how many grams of KClO₃ are needed to make 30 grams of KCl, you can use stoichiometry. First, you need to determine the molar mass of KClO₃ and KCl.

1. KClO₃ (Potassium Chlorate) has a molar mass:

K = 39.10 g/mol

Cl = 35.45 g/mol

O = 16.00 g/mol

Molar mass of KClO₃ = 39.10 + 3(35.45) + 3(16.00) = 122.45 g/mol

2. KCl (Potassium Chloride) has a molar mass:

K = 39.10 g/mol

Cl = 35.45 g/mol

Molar mass of KCl = 39.10 + 35.45 = 74.55 g/mol

Now, you can set up a ratio based on the balanced chemical equation:

2 moles of KClO₃ produce 2 moles of KCl

So, 122.45 grams of KClO₃ produce 74.55 grams of KCl.

To make 30 grams of KCl, you can set up a proportion:

(30 g KCl) / (74.55 g KCl) = (x g KClO₃) / (122.45 g KClO₃)

Now, solve for "x" (the grams of KClO₃ needed):

x = (30 g KCl * 122.45 g KClO₃) / 74.55 g KCl

x ≈ 48.87 grams of KClO₃ are needed to make 30 grams of KCl.

or

To determine how many grams of KClO₃ are needed to make 30 grams of KCl, you can use stoichiometry and the molar masses of the compounds involved. First, find the molar masses:

- KClO₃ (Potassium chlorate) has a molar mass of approximately 122.55 g/mol.

- KCl (Potassium chloride) has a molar mass of approximately 74.55 g/mol.

Now, set up a ratio using the balanced chemical equation:

2 moles of KClO₃ produce 2 moles of KCl.

So, in the equation, 2 moles of KClO₃ are required to produce 2 moles of KCl.

Now, calculate the moles of KCl in 30 grams:

Moles of KCl = Mass (g) / Molar mass (g/mol)

Moles of KCl = 30 g / 74.55 g/mol ≈ 0.402 moles

Since 2 moles of KClO₃ are required to produce 2 moles of KCl, you would need approximately 0.402 moles of KClO₃.

Now, convert moles of KClO₃ to grams:

Grams of KClO₃ = Moles of KClO₃ × Molar mass of KClO₃

Grams of KClO₃ = 0.402 moles × 122.55 g/mol ≈ 49.26 grams

So, you would need approximately 49.26 grams of KClO₃ to make 30 grams of KCl.

Explanation:

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Explanation:

To find out how many grams of KClO3 are needed to make 30 grams of KCl, you can use stoichiometry. First, you need to determine the molar mass of KCl and KClO3.

- Molar mass of KCl = 39.10 g/mol (potassium) + 35.45 g/mol (chlorine) = 74.55 g/mol

- Molar mass of KClO3 = 39.10 g/mol (potassium) + 35.45 g/mol (chlorine) + 3 * 16.00 g/mol (oxygen) = 122.55 g/mol

Now, you can set up a proportion to find the amount of KClO3 needed:

(30 g KCl) * (1 mol KClO3 / 2 mol KCl) * (122.55 g KClO3 / 1 mol KClO3) = 183.825 g KClO3

So, you would need approximately 183.825 grams of KClO3 to make 30 grams of KCl.

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