:-
If we add 1 to numerator, and subtract 1 from the denomination, a fraction reduce the 1.
It becomes ½ if we only add 1 to the denominator.
To Find :-
The Fraction
Solution :-
Let the fraction be x/y
According to the question,
⇒ x + 1/y - 1 = 1
⇒ x - y = - 2 ... (i)
⇒ x/y + 1 = 1/2
⇒ 2x - y = 1 ... (ii)
Subtracting equation (i) from equation (ii), we get
⇒ x = 3 ... (iii)
Putting this value in equation (i), we get
⇒ 3 - y = - 2
⇒ -y = 5
⇒ y = 5
Hence, the fraction 3/5
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Answers & Comments
:-
If we add 1 to numerator, and subtract 1 from the denomination, a fraction reduce the 1.
It becomes ½ if we only add 1 to the denominator.
To Find :-
The Fraction
Solution :-
Let the fraction be x/y
According to the question,
⇒ x + 1/y - 1 = 1
⇒ x - y = - 2 ... (i)
⇒ x/y + 1 = 1/2
⇒ 2x - y = 1 ... (ii)
Subtracting equation (i) from equation (ii), we get
⇒ x = 3 ... (iii)
Putting this value in equation (i), we get
⇒ 3 - y = - 2
⇒ -y = 5
⇒ y = 5
Hence, the fraction 3/5