answer: suppose divisor = x

therefore, quotient = 9x + 2

dividend = 460 and remainder = 5

dividend= divisor × quotient + remainder

460 = x ×( 9x + 2 ) + 5

460 = 9x² + 2x + 5

9x² + 2x + 5 - 460 = 0

9x² + 2x - 455 = 0

9x² - 63x + 65x - 455 = 0

9x(x - 7) + 65(x -7) = 0

9x + 65(x-7) = 0

9x + 65 = 0 or x -7 = 0

x = -65/9 or x = 7

however 460 is a no. that can only be devided by natural no. so x = 7

and,

quotient = 9×7+2 = 657

answer : q = 65 and d =