The heat released is 1530,375 kJ.

Step by Step explanation:

1. we get the value of Heat (Q) from this formula: ΔH = [tex]\frac{Q}{n}[/tex],

   where: ΔH = enthalpy change (kJ/mol) the value (-) is mean

                         exothermic reaction, and the value (+) is mean

                         endothermic reaction

                   n  = number of moles of substance (mol)

                   n  = (mass (gr) / Relative Molecular Mass (gr/mol)

we must find 'n' Methane,  It is known that the relative molecular mass of methane is 16 grmol. So,

n = 27.5 gr / 16 gr/mol.

n = 1,71875 mol    

because we want to find Q, the formula become:

   Q = ΔH x n

   Q = 890,4 kJ/mol x  1,71875 mol

   Q = 1530,375 kJ

So, in the combustion of 27,5 grams of methane, the heat released is 1530,375 kJ

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