It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100)
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100)
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - P
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values =5618−5000
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values =5618−5000= 618
Answers & Comments
Answer:
It is given that
It is given that Principal (P) = 5000
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100)
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100)
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - P
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values =5618−5000
It is given that Principal (P) = 5000Rate of interest (r) = 6% p.a.Period (n) = 2 years We Know that Amount = P(1+r/100) n Substituting the values =5000(1+6/100) 2 By further calculation = 5000×53/50×53/50= 5618Here CI = A - PSubstituting the values =5618−5000= 618
Answer:
It is given that
Principal (P) = 5000
Rate of interest (r) = 6% p.a.
Period (n) = 2 years
We Know that
Amount = P(1+r/100)
n
Substituting the values
=5000(1+6/100)
2
By further calculation
= 5000×53/50×53/50
= 5618
Here
CI = A - P
Substituting the values
=5618−5000
= 618
ummm
can someone send me bts link i dont have