2. Enchong jogs around a rectangular park which measures 120 m by 75 m. How far is the distance covered by Enchong if he goes around the park thrice?
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3. Julie has a square cartolina whose sides measure 40 cm each. She cuts the cartolina into two equal rectangles. Find the perimeter of one piece of rectangle.
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What is asked?
What are the given facts?
What is the process needed?
What is the number sentence?
What is the answer?
3. Julie has a square cartolina whose sides measure 40 cm each. She cuts the cartolina into two equal rectangles. Find the perimeter of one piece of rectangle.
What is asked?
What are the given facts?
What is the process needed?
What is the number sentence?
What is the answer?
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Answer:
2.first know the formula of the perimeter of a rectangle
F = 2(length) + 2(width)
then substitute the length and width to the given numbers, to determine the length you need to find what is bigger. the bigger number is the length and the shorter number is the width
F = 2(120) + 2(75)
next, perform the operations
F = 240 + 150
F = 390 m
3.120cm
The original perimeter of the square cartolina measuring 40cm each side.
P = 4s = 4(40cm) = 160cm
Cutting the square cartolina in half to form two rectangles would result to two sides of each rectangle will be half in measure of the original side.
P = 2sA + 2sB
P = 2(40cm) + 2(20cm)
P = 80cm + 40cm
P = 120cm
Step-by-step explanation
hope it helps :)