six possible outcomes multiplied by 6, which gives 36...It is only possible to get a sum grater than 10 if there comes 6,6 or 6,5! let 6 be (a) and 5 be (b)
so the probability that the sum of number on two dice is greater than 10 can be given by: (1/6×1/6)+(1/6×1/5)÷36= 11÷180 ,That is (1/a+1/a)+(1/a+1/b) / 36
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Answer:
let the first dice be a, and the second dice b
six possible outcomes multiplied by 6, which gives 36...It is only possible to get a sum grater than 10 if there comes 6,6 or 6,5! let 6 be (a) and 5 be (b)
so the probability that the sum of number on two dice is greater than 10 can be given by: (1/6×1/6)+(1/6×1/5)÷36= 11÷180 ,That is (1/a+1/a)+(1/a+1/b) / 36
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