Answer:
option c is correct
Step-by-step explanation:
Sn=n/2×(2a+(n-1)d)
n = ? d= 2root2 - root2 a= root2
Sn=n/2×(2root2+(n-1)(2root2-roo2)
Sn=n/root2×root2 × (2root2+2root2n - 2root2 - root2n+ root2)
Sn=n/root2×root2 × root2×(2n-n+1)
Sn=n(n+1)/root2
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Answers & Comments
Answer:
option c is correct
Step-by-step explanation:
Sn=n/2×(2a+(n-1)d)
n = ? d= 2root2 - root2 a= root2
Sn=n/2×(2root2+(n-1)(2root2-roo2)
Sn=n/root2×root2 × (2root2+2root2n - 2root2 - root2n+ root2)
Sn=n/root2×root2 × root2×(2n-n+1)
Sn=n(n+1)/root2
Sorry I can't upload pic of question because my internet network is too slow
Mark my answer as a brainlist