SCIENCE:
Here are the problems you're going to answer.
Copy and solve the ff problems in 1/2 crosswise.
1. A homozygous dominant round seed is crossed with wrinkled seed plant. Determine the genotypic and phenotypic ratios of their offsprings.
2. What would be the phenotype of offsprings when heterozygous round face man married an oval shaped face woman?
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Answers & Comments
Explanation:
1. The cross between a homozygous dominant round seed plant (RR) and a wrinkled seed plant (rr) can be represented as follows:
R R
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r|Rr | Rr
r| Rr| Rr
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Each offspring inherits one allele from each parent, so all the offspring will be heterozygous (Rr) for seed shape. The genotypic ratio of the offspring will be 100% Rr.
The phenotype of the offspring will be round seed shape, since the dominant allele (R) masks the recessive allele (r). Therefore, the phenotypic ratio of the offspring will be 100% round seeds.
2. The shape of the face is determined by multiple genes, so it is difficult to predict the exact phenotype of the offspring based on the information given. However, if we assume that the trait is determined by a single gene with two alleles (round face, R, and oval face, r), and that round face is dominant over oval face, the cross between a heterozygous round face man (Rr) and an oval face woman (rr) can be represented as follows:
R r
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r|Rr | rr
r|Rr | rr
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Each offspring has a 50% chance of inheriting the dominant allele (R) from the father, and a 50% chance of inheriting the recessive allele (r) from the mother. Therefore, the genotypic ratio of the offspring will be 50% Rr and 50% rr.
Since round face is dominant over oval face, the offspring with the Rr genotype will have a round face phenotype, while the offspring with the rr genotype will have an oval face phenotype. Therefore, the phenotypic ratio of the offspring will be 50% round face and 50% oval face.