using the resulting table of values represented in the preceding activity,(activity 1), determine the domain and the range. F1(x)=x-1/2 and f1(x)=x-4 Pah heply pooo
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Answer:
\: : \implies\sf \large A=\pi {( \frac{d}{2} )}^{2}:⟹A=π(2d)2
\implies\sf \large A=(3.14) {( \frac{5in}{2} )}^{2}⟹A=(3.14)(25in)2
\implies\sf \large A=(3.14) {( 2.5in)}^{2}⟹A=(3.14)(2.5in)2
\implies\sf \large A=(3.14)( {6.25in}^{2} )⟹A=(3.14)(6.25in2)
\implies\sf \large \purple{ Area=19.625 {in}^{2} }⟹Area=19.625in2
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