Answer:
lution: Note that in the obtuse-angled triangle ABC, CD represents the height. Hence, CD = 4cm . We know that,
Area = 1/2 * baseheight = 1/2 * ABCD
Thus, we need to find the length of base AB of the triangle. Since CD is the height, so CD 1 BD.
In right-angled triangle BCD, BD = 3cm
B * C ^ 2 = B * D ^ 2 + C * D ^ 2 (Pythagoras' theorem)
(5) ^ 2 = B * D ^ 2 + (4) ^ 2
B * D ^ 2 = 25 - 16 = 9
Now, AB + BD = AD
.. AB = AD - BD = 10 - 3 = 7 cm
Hence, area of Delta*ABC = 1/2 * ABCD
= 1/2 * 7 * 4 = 14c * m ^ 2
An - obtuse angled triangle ABC, where 4D = 10cm BC = 5cm
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Verified answer
Answer:
lution: Note that in the obtuse-angled triangle ABC, CD represents the height. Hence, CD = 4cm . We know that,
Area = 1/2 * baseheight = 1/2 * ABCD
Thus, we need to find the length of base AB of the triangle. Since CD is the height, so CD 1 BD.
In right-angled triangle BCD, BD = 3cm
B * C ^ 2 = B * D ^ 2 + C * D ^ 2 (Pythagoras' theorem)
(5) ^ 2 = B * D ^ 2 + (4) ^ 2
B * D ^ 2 = 25 - 16 = 9
Now, AB + BD = AD
.. AB = AD - BD = 10 - 3 = 7 cm
Hence, area of Delta*ABC = 1/2 * ABCD
= 1/2 * 7 * 4 = 14c * m ^ 2
An - obtuse angled triangle ABC, where 4D = 10cm BC = 5cm
Visit >