PHYSICS.
Trial
1.
2.
3.
Time(s)
1. 0.87seconds
2. 0.80seconds
3. 0.90seconds
MEASURE THE HEIGHT USING THE FORMULA: h= 1/2 a(g) t²
pasagot po pls kailangan ng ipass bukas
Trial
1.
2.
3.
Time(s)
1. 0.87seconds
2. 0.80seconds
3. 0.90seconds
MEASURE THE HEIGHT USING THE FORMULA: h= 1/2 a(g) t²
pasagot po pls kailangan ng ipass bukas
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Answers & Comments
h = (1/2) * a * t^2
where h is the height, a is the acceleration due to gravity (9.81 m/s^2), and t is the time.
Using the given times:
Trial 1: h = (1/2) * 9.81 m/s^2 * (0.87 s)^2 = 3.60 meters
Trial 2: h = (1/2) * 9.81 m/s^2 * (0.80 s)^2 = 3.14 meters
Trial 3: h = (1/2) * 9.81 m/s^2 * (0.90 s)^2 = 3.96 meters
Therefore, the measured heights for the three trials are 3.60 meters, 3.14 meters, and 3.96 meters.