Answer:

9x^2-72=0

a = 9; b = 0; c = -72;

Δ = b2-4ac

Δ = 02-4·9·(-72)

Δ = 2592

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

The end solution:

Δ−−√=2592−−−−√=1296∗2−−−−−−√=1296−−−−√∗2√=362√

x1=−b−Δ√2a=−(0)−362√2∗9=0−362√18=−362√18=−22√

x2=−b+Δ√2a=−(0)+362√2∗9=0+362√18=362√18=22√