Answer:
[tex]add . \\ 2 {x}^{3} - 9 {x}^{2} + 6 + 3 {x}^{3} - 9 + 6{x}^{2} + {x}^{3} - 10 {x}^{2} \\ = 7 {x}^{3} - 13 {x}^{2} - 3[/tex]
[tex]subtraction. \\ 1).2p - 6q - 10 - 6p - q - 3 \\ = - 4p - 7q - 13\\ 2).9 {x}^{2} - 2 - 10x + 11 - 3{x}^{3} + 5x - 4 \\ = - 3 {x}^{3} +9 {x}^{2} - 5x + 5 [/tex]
[tex]multiple:
1). (2x+4)(3x+2) \\ = 6 {x}^{2} + 4x + 12x + 8 \\ = 6 {x}^{2} + 16x + 8 \\ = 2(3 {x}^{2} + 4x + 2) \\ \\
2).(3x+6)(3x+6) \\ = 9 {x}^{2} + 18x + 18x + 36 \\ = 9 {x}^{2} + 36x + 36 \\ = 9( {x}^{2} + 4x + 4 )\\ \\
3).(5x-4)(5x+4) \\ = 25 {x}^{2} + 20x - 20x - 16 \\ = 25 {x}^{2} - 16 \\ \\
4).(2x-6)(2x-6) \\ = 4 {x}^{2} - 12x - 12x + 36\\ =4( {x}^{2} - 6 + 9) \\
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Answers & Comments
Answer:
[tex]add . \\ 2 {x}^{3} - 9 {x}^{2} + 6 + 3 {x}^{3} - 9 + 6{x}^{2} + {x}^{3} - 10 {x}^{2} \\ = 7 {x}^{3} - 13 {x}^{2} - 3[/tex]
[tex]subtraction. \\ 1).2p - 6q - 10 - 6p - q - 3 \\ = - 4p - 7q - 13\\ 2).9 {x}^{2} - 2 - 10x + 11 - 3{x}^{3} + 5x - 4 \\ = - 3 {x}^{3} +9 {x}^{2} - 5x + 5 [/tex]
[tex]multiple:
1). (2x+4)(3x+2) \\ = 6 {x}^{2} + 4x + 12x + 8 \\ = 6 {x}^{2} + 16x + 8 \\ = 2(3 {x}^{2} + 4x + 2) \\ \\
2).(3x+6)(3x+6) \\ = 9 {x}^{2} + 18x + 18x + 36 \\ = 9 {x}^{2} + 36x + 36 \\ = 9( {x}^{2} + 4x + 4 )\\ \\
3).(5x-4)(5x+4) \\ = 25 {x}^{2} + 20x - 20x - 16 \\ = 25 {x}^{2} - 16 \\ \\
4).(2x-6)(2x-6) \\ = 4 {x}^{2} - 12x - 12x + 36\\ =4( {x}^{2} - 6 + 9) \\
[/tex]