Step-by-step explanation:

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Answer:

Correct option is A

Let sin(A+B)= (√3/2)

⇒sin(A+B)=sin60 ⁰

⇒A+B=60 ...(i)

Let cos(A−B)= (√3/2)

⇒cos(A−B)=cos30 ⁰

⇒A−B=30 ⁰ ...(ii)

Adding (1) and (2), we get

2A=90

A=45 ⁰

Subtracting (1) and (2), we have

2B=30

B=15 ⁰