1.x = 6 and y = 4 a if x directly varies to y, then k= b. if x inversely varies to y, then k= c. if y directly varies to the square of x, then k= d. ify inversely varies to the square ofx, then k= e. if x inversely varies to the square root of y, then k= please paki sagot matino nonsene=report paki sagot yung matalino sa math l. Created by sicatfate. Math

✒️VARIATIONSx = 6 and y = 4a. If x directly varies to y, then k is?b. If x inversely varies to y, then k is?c. If y directly varies to the square of x, then k is?d. If y inversely varies to the square of x, then k is?e. If x inversely varies to the square root of y, then k is?a. If x directly varies to y, then k is?b. If x inversely varies to y, then k is?c. If y directly varies to the square of x, then k is?d. If y inversely varies to the square of x, then k is?e. If x inversely varies to the square root of y, then k is?(ノ^_^)ノ

1.x = 6 and y = 4 a if x directly varies to y, then k= b. if x inversely varies ...

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✒️VARIATIONS

$••••••••••••••••••••••••••••••••••••••••••••••••••$

$\large\underline{\mathbb{GIVEN}:}$

x = 6 and y = 4

$\large\underline{\mathbb{PROBLEMS}:}$

a. If x directly varies to y, then k is?

b. If x inversely varies to y, then k is?

c. If y directly varies to the square of x, then k is?

d. If y inversely varies to the square of x, then k is?

e. If x inversely varies to the square root of y, then k is?

$••••••••••••••••••••••••••••••••••••••••••••••••••$

$\large\underline{\mathbb{ANSWERS}:}$

$\qquad \Large a. \: \rm{k = \large \frac{\,3\,}{2}} \\$

$\qquad \Large b. \: \rm{k = 24}$

$\qquad \Large c. \: \rm{k = \large \frac{\,1\,}{9}} \\$

$\qquad \Large d. \: \rm{k = 144 }$

$\qquad \Large e. \: \rm{k = 12}$

$••••••••••••••••••••••••••••••••••••••••••••••••••$

$\large\underline{\mathbb{SOLUTION}:}$

a. If x directly varies to y, then k is?

$x = ky$

$6 = k(4)$

$\frac{\,6\,}{4} = \frac{\,k(4)\,}{4} \\$

$\frac{\,3\,}{2} = k \\$

b. If x inversely varies to y, then k is?

$x = \frac{\,k\,}{y} \\$

$6 = \frac{\,k\,}{4} \\$

$6(4) = \frac{\,k\,}{4}(4)$

$24 = k$

c. If y directly varies to the square of x, then k is?

$y = kx^2$

$4 = k(6)^2$

$4 = k(36)$

$\frac{4}{\,36\,} = \frac{\,k(36)\,}{36} \\$

$\frac{\,1\,}{9} = k \\$

d. If y inversely varies to the square of x, then k is?

$y = \frac{\,k\,}{\,x^2\,} \\$

$4 = \frac{k}{\,6^2\,} \\$

$4 = \frac{k}{\,36\,} \\$

$4(36) = \frac{k}{\,36\,}(36) \\$

$144 = k$

e. If x inversely varies to the square root of y, then k is?

$x = \frac{k}{\,\sqrt{y}\,}\\$

$6 = \frac{k}{\,\sqrt{4}\,}\\$

$6 = \frac{k}{\,2\,}\\$

$6(2) = \frac{k}{\,2\,}(2)\\$

$12 = k$

$••••••••••••••••••••••••••••••••••••••••••••••••••$

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$\huge \red{\boxed{\boxed {\colorbox{black} {\sf {Answer}}}}}$

1.x = 6 and y = 4

a if x directly varies to y, then k= $\boxed {\sf \green {k = \frac{2}{3}}}$

b. if x inversely varies to y, then k= $\boxed {\sf \green {k = 24 }}$

c. if y directly varies to the square of x, then k= $\green {\sf { k = \frac{1}{9}}}$

d. ify inversely varies to the square ofx, then k= $\green {\sf {k = 144}}$

e. if x inversely varies to the square root of y, then k= $\green {\sf {k = 12}}$

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✒️VARIATIONS

a. If x directly varies to y, then k is?

b. If x inversely varies to y, then k is?

c. If y directly varies to the square of x, then k is?

d. If y inversely varies to the square of x, then k is?

e. If x inversely varies to the square root of y, then k is?

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Verified answer

✒️VARIATIONS

a. If x directly varies to y, then k is?

b. If x inversely varies to y, then k is?

c. If y directly varies to the square of x, then k is?

d. If y inversely varies to the square of x, then k is?

e. If x inversely varies to the square root of y, then k is?

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