Answer:

1. Using the formula for Charles's Law (V1/T1 = V2/T2), we can find V2:

V1 = 0.50 L

T1 = 25°C

T2 = 100°C

V2 = ?

(V1 / T1) = (V2 / T2)

(0.50 L / 25°C) = (V2 / 100°C)

Cross-multiplying:

(0.50 L) * (100°C) = (V2) * (25°C)

50 L°C = 25 V2

Dividing both sides by 25:

50 L°C / 25 = V2

V2 = 2 L

Therefore, V2 is equal to 2 liters.

2. Applying Charles's Law again, we can find V2:

V1 = 100 L

T1 = 15.2°C

T2 = 0.61°C

V2 = ?

(V1 / T1) = (V2 / T2)

(100 L / 15.2°C) = (V2 / 0.61°C)

Cross-multiplying:

(100 L) * (0.61°C) = (V2) * (15.2°C)

61 L°C = 15.2 V2

Dividing both sides by 15.2:

61 L°C / 15.2 = V2

V2 ≈ 4.013 L (rounded to three decimal places)

Therefore, V2 is approximately 4.013 liters.