1.Two blocks of masses 5kg and 10kg are connected by a mass less spring.A force of 10N acts on 10kg masss.At the instant 5 kg mass has an insertion of 0.2ms^(-2) the acceleration of 10kg mass would be A) 0.1ms^(-2) B) 0.9ms^(-2) C) 0.6ms^(-2) D) 0.9ms^(-2)
The most congenial answer will be marked brainliest
The most congenial answer will be marked brainliest
Answers & Comments
Answer:
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Explanation:
To find the acceleration of the 10 kg mass when the 5 kg mass has an acceleration of 0.2 m/s², we can use Newton's second law of motion. The force on an object is equal to the mass of the object multiplied by its acceleration.
For the 5 kg mass:
Force = 5 kg * 0.2 m/s² = 1 N
Now, to find the acceleration of the 10 kg mass, we'll consider the force acting on it, which is 10 N. The force on the 10 kg mass is due to the spring and the applied force:
10 N (applied force) - 1 N (force on the 5 kg mass) = 9 N
Now, use Newton's second law for the 10 kg mass:
Force = Mass * Acceleration
9 N = 10 kg * Acceleration
Now, solve for acceleration:
Acceleration = 9 N / 10 kg = 0.9 m/s²
So, the acceleration of the 10 kg mass is 0.9 m/s².
The correct answer is B) 0.9 m/s².