1)There are always 4 bars of chocolates left when boxes of chocolate are shared equally among 8, 10 or 12 children. Find the smallest number of chocolates in the box.
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2)There are 117 boys and 135 girls joined in the field trip. The teacher in-Charge decided to group them. If each group will have an equal number of members, how many groups can be formed from all students joined in the field trip?
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Answer: (give the complete answer) ________________________________________________
2)There are 117 boys and 135 girls joined in the field trip. The teacher in-Charge decided to group them. If each group will have an equal number of members, how many groups can be formed from all students joined in the field trip?
Understand:
Asked:________________________________________________________________________
Given: ___________ ________
Plan:
How will I solve the problem? ______________________________________________________
Solve:
How is the solution done? _________________________________________________________
Answer: (give the complete answer) ________________________________________________
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Least Common Multiple and Greatest Common Factor:
1. Understand:
Asked: The smallest number of chocolates in the box
Given: 4 bars of chocolates
8, 10, or 12 children
Plan:
I will solve the problem using the least common multiple of 8, 10, and 12.
Solve:
The solution is done by finding the least common multiple of 10 and 12.
8 - 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120
10 - 10 ,20 ,30 ,40, 50, 60, 70, 80, 90 ,100, 110, 120
12 - 12, 24, 36, 48, 60, 72, 84, 96, 108, 120_____________
The least common multiple of 8, 10, and 12 is 120.
Given that the least common multiple is 120, we will add 4 to it since it is stated in the problem that there are always 4 bars of chocolates left when it is distributed to 10 or 12 children thus,
120 + 4 = 124
Answer:
Therefore, the smallest number of chocolates in the box is 124.
2. Understand:
Asked: The number of groups that can be formed from all the students who have joined the field trip.
Given: 117 boys
135 girls
Plan:
I will solve the problem using the greatest common factor.
Solve:
The solution is done by finding the greatest common factor of 117 and 135.
117 - 1, 3, 9, 13, 39, 117
135 - 1, 3, 5, 9, 15, 27, 135
Common Factors: 1, 3, 9
Choose the greatest.
The greatest common factor of 117 and 135 is 9.
Given that the greatest common factor of 117 and 135 is 9. Let us get the total number of participants then divide it by the greatest common factor to get the number of groups that can be formed.
117 boys + 135 girls = 252 participants
252 participants ÷ 9 = 28 groups
Answer:
Therefore, there are 28 groups in all.
Keywords: least common multiple, greatest common factor
How to find the least common multiple and greatest common factor: brainly.ph/question/658376
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