Answer:
Step-by-step explanation:
1) which right triangle? the triangle PQR?
if so:
sin θ = = 5 / 13 = 0.384614
cos θ = = 12 /13 = 0.923077
tan θ = = = 5/12 = 0.41666667
cosec θ = hypotenuse/opposite = 1/sin θ = 13/5 = 2.6
sec θ = hypotenuse/adjacent = 1/cos θ = 13/12 = 1.083333
cot θ = adjacent /opposite = 1/tan θ = cosθ / sinθ = 12/5 = 2.4
2)again:
sin θ = 5/13 = 0.384614
cos θ= 12 /13 = 0.923077
tan θ = 5/12 = 0.41666667
or
tan θ= sin θ/cos θ = 0.384614 / 0.923077 =0.41666667
cot θ = 12/5 = 2.4
cot θ =cos θ / sin θ = 0.923077 / 0.384614 = 2.4
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Answers & Comments
Answer:
Step-by-step explanation:
1) which right triangle? the triangle PQR?
if so:
sin θ =
= 5 / 13 = 0.384614
cos θ =
= 12 /13 = 0.923077
tan θ =
=
= 5/12 = 0.41666667
cosec θ = hypotenuse/opposite = 1/sin θ = 13/5 = 2.6
sec θ = hypotenuse/adjacent = 1/cos θ = 13/12 = 1.083333
cot θ = adjacent /opposite = 1/tan θ = cosθ / sinθ = 12/5 = 2.4
2)again:
sin θ = 5/13 = 0.384614
cos θ= 12 /13 = 0.923077
tan θ = 5/12 = 0.41666667
or
tan θ= sin θ/cos θ = 0.384614 / 0.923077 =0.41666667
cot θ = 12/5 = 2.4
or
cot θ =cos θ / sin θ = 0.923077 / 0.384614 = 2.4