Answer:
1.z=kxy
10=k(2)(5)
10/10=10k/10
k=1
z=(1)(6)(12)
z=72
2.z=kxy
2=k(6)(4)
2/24=24k/24
k=1/12
4=(1/12)(x)(8)
4=2/3x
4/3/2=x
x=6
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Answer:
1.z=kxy
10=k(2)(5)
10/10=10k/10
k=1
z=(1)(6)(12)
z=72
2.z=kxy
2=k(6)(4)
2/24=24k/24
k=1/12
4=(1/12)(x)(8)
4=2/3x
4/3/2=x
x=6