1)Find the length of the perpendicular drawn on x axis from (5, - 7)
2)What is the co-ordinate of the point on the negative side of x-axis which is at a distance of 3 units from the origin
3) 1)The ratio of the angles of a quadrilateral is 1:2:3:4. Find the angles.
Answers & Comments
EXPLANATION.
Question = 1.
Find the length of the perpendicular drawn on x - axis from (5, -7).
As we know that,
Distance formula.
⇒ d = √[(x₁ - x₂)² + (y₁ - y₂)²].
Using this formula in this question, we get.
Coordinates on x - axis = (5, 0).
⇒ d = √[(5 - 5)² + (- 7 - 0)²].
⇒ d = √[(0)² + (-7)²].
⇒ d = √(0 + 49).
⇒ d = √49.
⇒ d = 7.
∴ The length of the perpendicular drawn on x - axis from (5, -7) is 7.
Question = 2.
What is the Co-ordinate of the point on the negative side of x - axis which is at a distance of 3 units from the origin.
As we know that,
Coordinates axis of x - axis on negative side is = (- x, 0).
Where x is the distance from the origin.
∴ The Coordinate is = (- 3, 0).
Question = 3.
The ratio of the angles of a quadrilateral is 1 : 2 : 3 : 4. find the angles.
As we know that,
Sum of angles of a quadrilateral is equal to 360°.
Let us assume that,
Angles be : x, 2x, 3x, 4x.
⇒ x + 2x + 3x + 4x = 360°.
⇒ 10x = 360°.
⇒ x = 36°.
Angles be,
⇒ x = 36°.
⇒ 2x = 2(36°) = 72°,
⇒ 3x = 3(36°) = 108°.
⇒ 4x = 4(36°) = 144°.
∴ The angles are 36°, 72°, 108°, 144°.
Answer:
kindly check my solution if u have doubts then ask me
Step-by-step explanation:
ye sab graphs analysing ke upar agr bhai ye question mcq mai hota to sirf 5 snds anwer deta bss terko
ki x axis jitna perpendicular utna mera y coordinate hoga prr mai janta hu ki terko sdpubt ayyega ki y coordinate to mai to (x,y) hota hai nhi ye galat hai khali smjh ki y coordinate only y ka value dega always remember,
next doubt hai
axis or coordinate mai diff hai
axis is plane which is formed by horizontal and vertical line , plane is two dimensional representation of any objects
define kiya hai ki vertical line ka mtlb y axis
horizontal line ka mtlb x axis