1.Find the equation of the line that passes through the point (-5,9) with slope ...

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October 2022 1 1 Report

1.Find the equation of the line that passes through the point (-5,9) with slope of 5.
2.Find the equation of the line that passes through the point (-7,5 with slope of ⅔.
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Equation of the line

$\tt \Large \blue{\bold{y - y_1 = m (x - x_1)}}$

$\:$

1. Find the equation of the line that passes through the point (-5,9) with slope of 5.

$\tt \Large \rightarrow \blue{\bold{y - y_1 = m (x - x_1)}}$

$\tt \large \rightarrow y - 9 = 5 (x - (-5))$

$\tt \large \rightarrow y - 9 = 5 (x + 5)$

$\tt \large \rightarrow y - 9 = 5x + 25$

$\tt \large \rightarrow y = 5x + 25 + 9$

$\tt \Large \rightarrow \purple{\bold{y= 5x + 34}}$

Answer:

$\tt \Large \purple{\bold{y= 5x + 34}}$

$\:$

2. Find the equation of the line that passes through the point (-7,5) with slope of ⅔.

$\tt \Large \blue{\bold{y - y_1 = m (x - x_1)}}$

$\tt \large \rightarrow y - 5 = \frac{2}{3} (x - (-7))$

$\tt \large \rightarrow y - 5 = \frac{2}{3} (x + 7)$

$\tt \large \rightarrow y - 5 = \frac{2}{3} \times x + \frac{2 \times 7}{3}$

$\tt \large \rightarrow y - 5 = \frac{2}{3}x + \frac{14}{3}$

$\tt \large \rightarrow y = \frac{2}{3}x + \frac{14}{3} + 5$

$\tt \large \rightarrow y = \frac{2}{3}x + \frac{14}{3} + \frac{5 \times 3}{3}$

$\tt \large \rightarrow y = \frac{2}{3}x + \frac{14}{3} + \frac{15}{3}$

$\tt \Large \rightarrow \purple{\bold{y= \frac{2}{3}x + \frac{29}{3}}}$

Answer:

$\tt \Large \purple{\bold{y= \frac{2}{3}x + \frac{29}{3}}}$

$\:$

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Verified answer

Equation of the line

1. Find the equation of the line that passes through the point (-5,9) with slope of 5.

Answer:

2. Find the equation of the line that passes through the point (-7,5) with slope of ⅔.

Answer:

Add an Answer

please paki help please

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