Hello, I hope you are having a nice day.

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Please remember that the sides of a square are equal.

So if we are given one side of a square, we can determine the other three sides.

Now, the formula for the area of a square is

[tex]\boxed{\pmb{A=a^{2} }}[/tex]

In this formula,

A stands for the Area

a stands for the length of one of the sides

Notice that a is squared. This means we multiply a times itself.

We know the value of a, which equals 8.

Plug in the value of a:

[tex]\boxed{A=8^2}[/tex]

[tex]\boxed{\rm{A=64cm^2}}[/tex]

cm² = square centimetres

[tex]\rule{270}{2}[/tex]

True or False?

First, we need to find the area of a rectangle, which is

[tex]\boxed{A=LW}[/tex]

Where

L -> Length

W -> Width

In this case, L is 10 and W is 5.

Plug in the values:

[tex]\boxed{A=5*10}[/tex]

[tex]\boxed{A=50ft^2}[/tex]

That's the area of a rectangle. Now, let's find the area of a square. Remember, the formula is

[tex]\boxed{A=a^2}[/tex]

a=10:

[tex]\boxed{A=10^2}[/tex]

[tex]\boxed{A=100ft^2}[/tex]

Is this statement true or false? No, the area of a rectangle with sides equal to 10 and 5 is not equal to the area of a square, whose side is equal to 10.

[tex]\rule{270}{2}[/tex]

True or false?

The area of a triangle is (b×h)÷2.

This statement is true, since the area of a triangle is indeed (b×h)÷2.

[tex]\rule{270}{2}[/tex]

True or false?

Two congruent triangles have equal measurements.

Yes, this statement is true; if triangles have different measurements, then they are not congruent.

If triangles have measurements that are proportional, then they are similar triangles.

[tex]\rule{270}{2}[/tex]

True or false?

In solving for the area of polygons the answer is in square units.

Yes. When we solve for the area of any polygon, the answer is in square units.

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Hope you find it helpful.