Answer:
3/4 in short form
Step-by-step explanation:
[tex] \tantheta \: = \frac{1}{2 \: \\} [/tex]
therefore
[tex] \sin(theta = 1) and \cos(h theta) \: = 2 [/tex]
so
[tex] \frac{ \cos(theta) }{ \sin(theta) } = \frac{2}{1} [/tex]
+
[tex] \frac{ \sin(theta) }{1 + \cos(theta) } = \frac{1}{ 1 + 2} [/tex]
=
[tex] \frac{2}{1} + \frac{1}{3} = \frac{3}{4} [/tex]
you also check once again that I am right or not
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Answer:
3/4 in short form
Step-by-step explanation:
[tex] \tantheta \: = \frac{1}{2 \: \\} [/tex]
therefore
[tex] \sin(theta = 1) and \cos(h theta) \: = 2 [/tex]
so
[tex] \frac{ \cos(theta) }{ \sin(theta) } = \frac{2}{1} [/tex]
+
[tex] \frac{ \sin(theta) }{1 + \cos(theta) } = \frac{1}{ 1 + 2} [/tex]
=
[tex] \frac{2}{1} + \frac{1}{3} = \frac{3}{4} [/tex]
you also check once again that I am right or not