Verified answer

Answer:

1) image is formed at (-3.333....m)

2) image is real and inverted and is b/w c and f

Explanation:

Given:

object distance, u = -5m

image distance, v = ?

focal length of mirror, f = -2m

type of mirror = concave mirror

To find:

1) distance of image from the mirror i.e. v

2) nature of image

Solution

1) u = -5m                                                                                                (given)

   f = -2m                                                                                                (given)        

by mirror formula

1/f = 1/u + 1/v

putting values in above eq. we get

(-1/2) = 1/v + (-1/5)

1/v = (-1/2) + 1/5

1/v = (-5/10) + 2/10 = (-3/10)

⇒ v = (-10/3)m = -3.333.....m

∴ image distance, v = (-3.333.....m)

2)

f = -2m                                                                                                     (given)

∴ center, c = 2f = -4m

now, we know that when u is numerically bigger than c

the object is kept beyond c.

and when object is kept beyond c, the image is formed between c and f

which in this case are -4m and -2m respectively.

we can verify this as the image distance is found to be (-3.333.....m), which is b/w -2m and -4m.

now, when image is formed b/w c and f the image is real and inverted.

∴ the nature of the image formed is real and inverted and b/w c and f.

thank you......

hope this helps you.........