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Answer:

1. When the stone is dropped from the rooftop of a building, its velocity will be zero at first, as it is not moving.

• As it falls, its velocity will increase due to the acceleration of gravity, which is approximately 9.8 meters per second squared. After 3 seconds, the velocity of the stone will be 29.4 meters per second, assuming that air resistance is negligible.

• The displacement of the stone after 3 seconds can be calculated using the equation S = ut + (1/2)at^2, where S is the displacement, u is the initial velocity (which is zero), a is the acceleration due to gravity, and t is the time elapsed. Plugging in the values, we get:

S = 0 + (1/2)(9.8)(3)^2 = 44.1 meters

Therefore, the displacement of the stone after 3 seconds is 44.1 meters.

2. The distance fallen by the male bungee jumper can be calculated using the equation S = (1/2)gt^2, where S is the distance fallen, g is the acceleration due to gravity (which is approximately 9.8 meters per second squared), and t is the time elapsed.

Plugging in the values, we get:

S = (1/2)(9.8)(1.5)^2 = 11.025 meters

Therefore, the male bungee jumper falls a distance of 11.025 meters during the 1.5 seconds of free fall.

3. The velocity with which the stone hits the water can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration due to gravity, and s is the displacement (which is equal to the height of the bridge, 30 meters, in this case). Plugging in the values, we get:

v^2 = 0 + 2(9.8)(30) = 588

v = sqrt(588) = 24.25 meters per second

Therefore, the stone hits the water with a velocity of approximately 24.25 meters per second.