Explanation:
ANSWER
In the first case he gains 10%
∴ C. P. of the first car
=
110
100×9900
=Rs.9000
In the second case he loses 10%
∴ C. P. of the second car
90
=Rs.11000
∴ Total cost of both cars
=9000+11000=Rs.20000
∴ Total S. P. of both cars
=2×9900=Rs.19800
∴ Total loss =20000−19800=Rs.200
∴ % of loss =
20000
200×100
=1%
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Answers & Comments
Explanation:
ANSWER
In the first case he gains 10%
∴ C. P. of the first car
=
110
100×9900
=Rs.9000
In the second case he loses 10%
∴ C. P. of the second car
=
90
100×9900
=Rs.11000
∴ Total cost of both cars
=9000+11000=Rs.20000
∴ Total S. P. of both cars
=2×9900=Rs.19800
∴ Total loss =20000−19800=Rs.200
∴ % of loss =
20000
200×100
=1%