Here 1712040,1704382 and 1702497 are all 7−digits numbers in which the same numbers 1 and 7 are placed at ten lakhs and lakhs places respectively whereas the digits in ten thousands place are 1,0 and 0
Hence 1712040 is the largest number and the digits in the remaining two numbers at thousands place are 4 and 2
Since 4>2
Therefore 1704382>1702497
201200,200175 and 199988 are 6−digits numbers in which 2 and 1 are at lakhs place respectively
Answers & Comments
Answer:
1712040 > 1704382 > 1702497 > 201200 > 200175 > 199988
Hope this satisfied you.....
Answer:
The given numbers in the descending order are:
1712040>1704382>1702497>201200>200175>199988
Step-by-step explanation:
Here 1712040,1704382 and 1702497 are all 7−digits numbers in which the same numbers 1 and 7 are placed at ten lakhs and lakhs places respectively whereas the digits in ten thousands place are 1,0 and 0
Hence 1712040 is the largest number and the digits in the remaining two numbers at thousands place are 4 and 2
Since 4>2
Therefore 1704382>1702497
201200,200175 and 199988 are 6−digits numbers in which 2 and 1 are at lakhs place respectively
Since 2 is greater than 1
Therefore 201200>200175
Thus 199988 is the smallest number
The given numbers in the descending order are:
1712040>1704382>1702497>201200>200175>199988