Answer:
12cm
Step-by-step explanation:
Area = 90cm
length = 15cm
height = x
[tex]90 = \frac{1}{2} \times x \times 15 \\ \\ 90 = \frac{15}{2} x \\ \\ 90 \times 2 = 15x \\ \\ 180 = 15x \\ \\ \frac{180}{15} = x \\ \\ 12 = x[/tex]
Hence,12cm is height.
Height AM= 12 cm
Given,
The area of ΔABC = 90 [tex]cm^{2}[/tex]
BC= 15cm
To find AM.
Let us construct a Triangle and represent the given information.
The height AM is perpendicular to the Base BC
hence, area of ΔABC= [tex]\frac{1}{2} \times (base) \times height[/tex]
90 = [tex]\frac{1}{2} ( BC \times AM)[/tex]
180 = 15 × AM
AM= [tex]\frac{180}{15}[/tex]
∴ AM= 12 cm
The Perpendicular height (AM) with respective base (BC) is 12 cm
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Verified answer
Answer:
12cm
Step-by-step explanation:
Area = 90cm
length = 15cm
height = x
[tex]90 = \frac{1}{2} \times x \times 15 \\ \\ 90 = \frac{15}{2} x \\ \\ 90 \times 2 = 15x \\ \\ 180 = 15x \\ \\ \frac{180}{15} = x \\ \\ 12 = x[/tex]
Hence,12cm is height.
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Answer:
Height AM= 12 cm
Step-by-step explanation:
Given,
The area of ΔABC = 90 [tex]cm^{2}[/tex]
BC= 15cm
To find AM.
Let us construct a Triangle and represent the given information.
The height AM is perpendicular to the Base BC
hence, area of ΔABC= [tex]\frac{1}{2} \times (base) \times height[/tex]
90 = [tex]\frac{1}{2} ( BC \times AM)[/tex]
180 = 15 × AM
AM= [tex]\frac{180}{15}[/tex]
∴ AM= 12 cm
The Perpendicular height (AM) with respective base (BC) is 12 cm