Surface Area

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

Question:

A cone has a radius of 9 cm and slant height of 12 cm. Find its surface area.

• [tex] \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{l} \sf{A. 593.46 cm^{2} } \\ \sf{B. 693.46 cm^{2} } \\ \sf{C. 793.46 cm^{2} } \\ \sf{D. 893.46 cm^{2} } \end{array}}\end{gathered} \end{gathered}\end{gathered} [/tex]

Answer:

[tex] \huge \underline{\boxed{\sf \red{A. \: 593.46 \: {cm}^{2} }}}[/tex]

To solve for the surface area of cone, you use this formula [tex]\tt{SA \: = \: \pi r s + \pi {r}^{2} }[/tex].

• [tex]\large\tt{SA \: = \: \pi r s + \pi {r}^{2} }[/tex]
• [tex]\large\tt{SA \: = \: 3.14(9cm)12cm + 3.14 ({9cm}^{2}) }[/tex]
• [tex]\large\tt{SA \: = \: 3.14( {\red1}{\red0}{\red 8}{\red c}{\red m}) + 3.14 ({ {\red8}{\red1}{\red c}{\red m}}^{ {\red2}}) }[/tex]
• [tex]\large\tt{SA \: = \: {\red3}{\red3}{\red 9}{\red.}{\red1}{\red2}{\red c}{\red m} + { {\red2}{\red5}{\red4}{\red .}{\red3}{\red4} {\red c}{\red m} ^{ {\red2}}} }[/tex]
• [tex]\large\tt{SA \: = }[/tex] [tex]\large \: \tt\underline{\green{ 593.46 \: {cm}^{2}} }[/tex]

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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