Answer:

This can be solved using some simple algebra.

Let X equal the number of students in each group.

Thus:

Group 1: x

Group 2: x-8 (As it has 8 less students than group 1!)

Group 1 + Group 2 should equal 50. So we get:

x + x - 8 = 50

So we get 2x - 8 = 50

Add eight to both sides: 2x = 58

Divide both sides by 2: x = 29

So, Group 1 has 29 students in it. Let’s find how many Group 2 has by subbing it in:

(29)-8 = 21

I know it is rather moot to use algebra for such problems but this is a great way of understanding basic algebra!