13. A floor of a building consists of 2,500 tiles. All the tiles are rhombus shaped with diagonal 40 cm and 25 cm. Find the total cost of polishing the floor at the rate of ₹8 per square meter. same pinch again
he pranked me last week I guess
autocorrect piroblems :'(
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Verified answer
Step-by-step explanation:
A floor of a building consists of 2500 tiles.
first Diagonal of rhombus(d1) = 40 cm
Second Diagonal of rhombus ( d2) = 25 cm
therefore area of rhombus = 1/2 × d1 × d2 = 1/2 × 40 × 25 =500 sq. cm
Now, are of 1 tile = 500 sq. m
therefore area of 2500 tiles = 2500 × 500 = 1,250,000 sq. cm
Now we have to convert it in sq. m = 1250000/100 = 12500 sq. m
COST of polishing 1 sq. m of floor = Rs. 8
therefore, cost of polishing 12500 sq. m of floor = 8 × 12500 = Rs. 1,00,000
I hope this will help you, thank u