Answer:
do this process to ur question
Step-by-step explanation:
Clearly, 6,13,20,.....,216 is an A.P. with first term a=6 and common difference d=7.
Let there be n terms in the given A.P.
Then, a
n
=216
⟹a+(n+1)d=216
⟹6+7(n−1)=216 [∵a=6 and d=7]
⟹7n=217⟹n=31
Here, n is odd so (
2
n+1
)
th
i.e. (
31+1
=16
term is the middle term and is given by
a
16
=a+(16−1)d=1+15d=6+15×7=111
plz mark me as brainlist
6,13,20,.....,216 is an A.P. with first
term a-6 and common difference d=7.
Then, an=216
+a+(n+1)d=216
-6+7(n-1)-216
[a-6 and d=7]
-7n-217-n=31
Here, n is odd so (2n+1th Le.(231+1)th
=16th
a16
=a+(16-1)d=1+15d=6+15x7=111
my name is cladiya not Claudia
which standard Ur studying?
which school Ur ?
I am from Spartan international school (CBSE)
do U like K-pop, kdrama, Korean movie's?
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Verified answer
Answer:
do this process to ur question
Step-by-step explanation:
Clearly, 6,13,20,.....,216 is an A.P. with first term a=6 and common difference d=7.
Let there be n terms in the given A.P.
Then, a
n
=216
⟹a+(n+1)d=216
⟹6+7(n−1)=216 [∵a=6 and d=7]
⟹7n=217⟹n=31
Here, n is odd so (
2
n+1
)
th
i.e. (
2
31+1
)
th
=16
th
term is the middle term and is given by
a
16
=a+(16−1)d=1+15d=6+15×7=111
plz mark me as brainlist
Step-by-step explanation:
6,13,20,.....,216 is an A.P. with first
term a-6 and common difference d=7.
Let there be n terms in the given A.P.
Then, an=216
+a+(n+1)d=216
-6+7(n-1)-216
[a-6 and d=7]
-7n-217-n=31
Here, n is odd so (2n+1th Le.(231+1)th
=16th
term is the middle term and is given by
a16
=a+(16-1)d=1+15d=6+15x7=111
plz mark me as brainlist
my name is cladiya not Claudia
which standard Ur studying?
which school Ur ?
I am from Spartan international school (CBSE)
do U like K-pop, kdrama, Korean movie's?