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PROBABILITY

Problem:

Which problem below can be made to give a probability of 3/12?

A. A spinner has 3 sectors with colors: Red, Blue and Yellow. You spun a spinner once and flipped the coin once, What is the probability of getting a red spinner and a head on the coin?

Analysis for Option A: The sample space is 6. The probability of getting a red spinner and a head on the coin is 1/6.

B. The probability of getting a head and an odd number when a coin is flipped and a die is rolled at the same time.

Analysis for Option B: The sample space is 12. The probability of getting a head and an odd number when a coin is flipped and a die is rolled at the same time is 3/12, since the possible combinations are H-1, H-3 and H-5, where H stands for the head of the coin and 1, 3 and 5 are the numbers on the die.

C. The number of vowels can be drawn from the word TRIGONOMETRY.

Analysis for Option C: There are 12 letters in the word TRIGONOMETRY. We will consider each letter as unique letter. There are 4 vowels in the word. Therefore, the probability of the number of vowels can be drawn from the word TRIGONOMETRY is 4/12.

D. The probability of getting two heads when a coin is flipped 3 times.

Analysis for Option D: The sample space is 2 raised to 3 which is 8. The possible outcomes are:

1. H-H-H
2. T-T-T
3. H-H-T
4. H-T-H
5. T-H-H
6. T-T-H
7. T-H-T
8. H-T-T

Only outcomes 3, 4 and 5 got two heads when a coin is flipped. So the probability is 3/8.

Conclusion:

Therefore, the correct answer is letter B.

Learn more about probability:

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