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Answer:

Let Ajay age a, Sujay age s, and year before x,

Ajay age before x years=a-x

Sujay age before x years =s-x

Also, a+s=42 ……………… (i)

ajay is twice as old as sujay was x years ago

a=2(s-x)

a = 2s - 2x ……………………..(ii)

x years ago, Ajay age was Sujay's current age

a-x =s ………………………….(iii)

from (i)

s=42-a ………………………….(iv)

substitute s from (iv) in (iii)

a-x = 42 - a

x = 2a - 42 …………………..(v)

substitute s from (iv) and x from (v) in (ii)

a = 2(42-a) -2(2a-42)

a = 84 - 2a - 4a + 84

7a = 168

a = 24

Ajay’s age is 24