12. From a plane flying due to east at 265 m above sea level, the angles of depression of two ships sailing due to east measure 45°and 25°.How far apart are the ships?
A. 188.9 m
B. 189.8 m
C. 293.8 m
D. 303.3 m
with solution po patulong naman
A. 188.9 m
B. 189.8 m
C. 293.8 m
D. 303.3 m
with solution po patulong naman
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Answer:
its letter D
Step-by-step explanation:
Given
A plane flying due east at 265 m above sea level, the angles of depression of two ships sailing due east measure 35 degrees and 25 degrees.
What is the angle of depression?
The angle of elevation, the angle of depression is the angle at which you would draw a line from a point on a horizontal line to intersect another point that falls below the line.
The plane is at B and the two ships are at C and at D.
Then,
The angle of depression of C from B is ∠ OBC = ∠ ACB = 35°.
And the angle of depression of D from B is ∠ OBD = ∠ ADB = 25°.
Therefore,
The distance apart are the two ships is;
= 568.3 - 378.5 = 189.8 m
Hence, the distance apart is the two ships is 189.8 meters.
To know more about Angle of Depression click the link given below