Ans

To determine the mass of the copper 2 sulfate penta hydrate that is obtained, we first need to figure out the change in mass of copper to sulfate in the solution at 70 degrees celsius, vert versus the lower temperature at 0 degrees celsius. So the temperature- i'm sorry, the mass of the solution is 325 and that being the mass of the solution, we know what the higher temperature 32.0 grams of the copper 2 sulfate can dissolve in 100 grams will then subtract off the amount that remains after it cools To 0 degrees celsius will still have a mass of 325 grams, but now at 0 degrees celsius, only 12.5 grams of copper, 2 sulfate can be found in 100 grams of the solution. So this difference will correspond to the mass of copper 2 sulfate. That came out of solution 63.375 or 38 grams- copper, 2 sulfate. But we want to know the mass of copper to sulfate pentahydrate that came out so we'll go back to our 63.38 and convert these into moles 1 mole, copper, 2 sulfate pentahydrate is 159.61 grams. Then we recognize that 1 mole, copper, 2 sulfate can precipitate out 1 mole, copper, 2 sulfate pentahydrate. Then we can convert the moles of copper, 2 sulfate pentahydrate into grams copper, 2 sulfate pentahydrate by multiplying by its molar mass, which is 249.69 grams and would get a total of 99.1 grams. Copper, 2 sulfate pentahydrate coming out of solution. Hope that helps so the 2 significant figures- it's just 99.

Explanation:

hope it helps

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 gram of Copper sulphate in 350 g solution is 32 x 3.5 = 112

in term of mol = 112 / 159.5 = 0.7022

after crystallisation, gm of copper sulphate in the solution

= 43.75

in term of mole

43.75/159.5 = 0.2743

mole that got precipitated in hydrated form = 0.7022 - 0.2743 =0.4279

in terms of gm of hydrated copper sulphate = .4279 x mol weight of hydrated copper sulphate = .4279 x 249.5 = 106.76 g .

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