Answer:
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Step-by-step explanation:
The length of the log that remains after cutting off two pieces of lengths 23/5 m and 33/10 m from a log 11 m long can be found by subtracting the sum of the lengths of the two pieces from the original length of the log.
The sum of the lengths of the two pieces is:
23/5 + 33/10 = 46/10 + 33/10 = 79/10
Therefore, the length of the remaining log is:
11 - 79/10 = 110/10 - 79/10 = 31/10 m
So, the length of the remaining log is 31/10 m.
Length of remaining log is 3.1 m.
Given:
To Find:
Length of remaining log.
Calculation:
Length of the cut off pieces = 23/5 m and 33/10 m
Total length of the cut off pieces = 23/5 + 33/10 m
= 79/10 m
= 7.9 m
Total length of the log = 11 m
Total length of Cut off pieces = 7.9 m
Length of Remaining log = 11 - 7.9 m = 3.1 m
Hence, Length of remaining log is 3.1 m. ( ans. )
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Answers & Comments
Answer:
Mark me as brainlist please
Step-by-step explanation:
The length of the log that remains after cutting off two pieces of lengths 23/5 m and 33/10 m from a log 11 m long can be found by subtracting the sum of the lengths of the two pieces from the original length of the log.
The sum of the lengths of the two pieces is:
23/5 + 33/10 = 46/10 + 33/10 = 79/10
Therefore, the length of the remaining log is:
11 - 79/10 = 110/10 - 79/10 = 31/10 m
So, the length of the remaining log is 31/10 m.
Verified answer
Answer:
Length of remaining log is 3.1 m.
Step-by-step explanation:
Given:
To Find:
Length of remaining log.
Calculation:
Length of the cut off pieces = 23/5 m and 33/10 m
Total length of the cut off pieces = 23/5 + 33/10 m
= 79/10 m
= 7.9 m
Total length of the log = 11 m
Total length of Cut off pieces = 7.9 m
Length of Remaining log = 11 - 7.9 m = 3.1 m
Hence, Length of remaining log is 3.1 m. ( ans. )