Answer:
When 8 and 12 are in parallel
and 7.2 is in series with them
Net Resistance
10
7.2
+
12+8
8×12
=
72
20
96
48
120
=12Ω
Total current =
netR
V
12
6
=0.5Ω
Voltage across R
1
=iR
=0.5×7.2
=3.6 here is your answer hope you like it and please mark me as a brainlist
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Verified answer
Answer:
When 8 and 12 are in parallel
and 7.2 is in series with them
Net Resistance
10
7.2
+
12+8
8×12
=
10
72
+
20
96
=
10
72
+
10
48
=
10
120
=12Ω
Total current =
netR
V
=
12
6
=0.5Ω
Voltage across R
1
=iR
1
=0.5×7.2
=3.6 here is your answer hope you like it and please mark me as a brainlist