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Question 1:

Find three consecutive integers whose sum is 348.

Solution:

Let x be the first integer. Then let (x + 1) be the second integer. And let (x + 2) be the third integer. The sum of the three consecutive integers is 348.

• x + (x + 1) + (x + 2) = 348

Let's solve the integer.

• x + (x + 1) + (x + 2) = 348
• 3x + 3 = 348
• 3x = 348 - 3
• 3x = 345/3
• x = 115
• x + 1 = 116 and x + 2 = 117

Check:

Check and plug the integers if x = 115, x + 1 = 116 and x + 2 = 117.

• x + (x + 1) + (x + 2) = 348
• 115 + 116 + 117 = 348

Answer:

• Therefore, the 115, 116 and 117 are consecutive integers whose sum is 348.

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Question 2:

Find three consecutive integers whose sum is 255.

Solution:

Let x be the first integer. Then let (x + 1) be the second integer. And let (x + 2) be the third integer. The sum of the three consecutive integers is 255.

• x + (x + 1) + (x + 2) = 255

Let's solve the integer.

• x + (x + 1) + (x + 2) = 255
• 3x + 3 = 255
• 3x = 255 - 3
• 3x = 252/3
• x = 84
• x + 1 = 85 and x + 2 = 86

Check:

Check and plug the integers if x = 84, x + 1 = 85 and x + 2 = 86.

• x + (x + 1) + (x + 2) = 255
• 84 + 85 + 86 = 255

Answer:

• Therefore, the 84, 85 and 86 are consecutive integers whose sum is 255.

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