1. Write the opposite of loss of 700.
2. Write the prime factors of 36.
3. Draw a number line to locate on it.
4. Find the perimeter of an equilateral triangle whose side is 6cm.
5. Which is the smallest prime number?
6. Express 10 as improper fraction.
7. Sarita bought m of ribbon and Lalita bought m of ribbon. What is the total length of the ribbon bought?
8. Find the value of: 50- (-40) + (-2)
9. Perimeter of a square piece of cardboard is 36 sq. cm. What will be the side of the
cardboard?
10. Find the L.C.M. of 24 and 90.
11. What is the cost of tiling a rectangular plot of land 500m long and 200m wide at
the rate of Rs. 2 per sq.m.?
12. Using the divisibility test check if 297144 is divisible by 6 or not? 13. The length, breadth and height of a room are 825cm .675cm and 450cm respectively. Find the longest tape which can measure the three dimensions of the
room exactly.. 14. The sum of two integers is 48. If one of them is -24, find the other
please answer it quickly someone
Answers & Comments
Verified answer
1. Profit of 700
2. 2×2×3×3
3. Graphical question can't be expressed in texts.
4. The triangle is equilateral. Perimeter of Equilateral Triangle is 3×Sides
3×6 = 18 cm
5. 2 is the smallest prime number
6. 20/2, 30/3 etc.
7. Bought by Sarita = m metres
Bought by Lalita = m metres
Total = m+m = 2m metres
8. 50-(-40) + (-2)
On simplification,
50 + 40 - 2
By DMAS
90-2
= 88 is the answer
9. Question has errors, Perimeter is not measured in square units.
Area of Cardboard = 36 cm²
Side × Side = 36
Side = 6 cm
Perimeter of Cardboard = 36 cm
Side×4 = 36
Side = 9 cm
10. LCM of 24 and 90
Multiples of 24 = 2,3,4,6,8,12,24
Multiples of 90 = 2,3,5,6
We can see the least common number is 2
So LCM of 24 & 90 is 2
11. Length of Plot = 500 m
Breadth of Plot = 200 m
Cost = Rs. 2/sq m
Area of rectangle = length × breadth
Area of Rectangle = 500×200
= 100000 sq m
Cost of tiling = 2×100000 = 200000 Rs
12. I don't remember the divisibiltiy test