1. Which of the following is the correct solution set in solving the quadratic
inequality x²+ 3x - 18 < 0
A {x: 9<x< -2)
C.x: -6< x< 31
B. x:-9<x<2)
D. {X:6 X ≥ 0}
inequality x²+ 3x - 18 < 0
A {x: 9<x< -2)
C.x: -6< x< 31
B. x:-9<x<2)
D. {X:6 X ≥ 0}
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C. -6 and 3
x² + 3x - 18 < 0
write the inequality:
-6² + 33 - 18 < 0
substitute -6 for x and 3 for x:
-36 + 33 - 18 < 0
simplify:
-21 < 0
-21 is less than 0. so, (-6, 3) is a solution to an inequality.