1-: When suns altitude change from 30° to 60° the length of the shadow of tower is decrease by 17 m what is the height of tower?
option -:
35m
140 m
60.6
20.2
2-: Jilli buys two kind of cloths materials for school uniform shirt material that cost him ₹ 50 per meter and trouser material that cost him ₹ 90 per meter for everything metre of the shirt material he buys 2 m of the trouser material he sells the materials at 12% and 10% profit respectively he is total sale is rupees 3660 how much trouser material did he buys ?
solve with explanation and please don't Spam
option -:
35m
140 m
60.6
20.2
2-: Jilli buys two kind of cloths materials for school uniform shirt material that cost him ₹ 50 per meter and trouser material that cost him ₹ 90 per meter for everything metre of the shirt material he buys 2 m of the trouser material he sells the materials at 12% and 10% profit respectively he is total sale is rupees 3660 how much trouser material did he buys ?
solve with explanation and please don't Spam
Answers & Comments
Verified answer
Answer:
1. 60.6m
2. 200
Step-by-step explanation:
Let CD distance be X
In Δ ABC
Tan30° h/(X+70)
=1 / √3= h / (x + 70)
√3h = X + 70 - - (1)
In ADC
Tan60° = h/X
→ sqrt(3) = h / X
→ X = h / √3
Putting X in equation (1)
√3h= h/√3+ 70
→ 2h = 70√(3)
h = 60.6m
The height of the tower is 60.6 m.
Question No. 1:-
When suns altitude change from 30° to 60° the length of the shadow of tower is decrease by 17 m what is the height of tower?
Answer:-
60.6
Step-by-step explanation:
Given:
When sun's altitude changes from 30° to 60°, the length of the shadow of a tower decreases by 70 m.
Formula used:
Tanθ = Perpendicular/Base
Tan60o = √3
Tan30o = 1/√3
Calcuation:
Let CD distance be X
In Δ ABC
⇒ Tan30o = h/(X + 70)
⇒ 1/√3 = h/(X + 70)
⇒ √3h = X + 70 ----(1)
In Δ ADC
⇒ Tan60o = h/X
⇒ √3 = h/X
⇒ X = h/√3
Putting X in equation (1)
⇒ √3h = h/√3 + 70
⇒ 2h = 70√3
⇒ h = 60.6 m
∴ The height of the tower is 60.6 m.
Question No. 2:-
Jilli buys two kind of cloths materials for school uniform shirt material that cost him ₹ 50 per meter and trouser material that cost him ₹ 90 per meter for everything metre of the shirt material he buys 2 m of the trouser material he sells the materials at 12% and 10% profit respectively he is total sale is rupees 3660 how much trouser material did he buys ?
Answer:-
200m
Step-by-step explanation:
According to the question, Trouser material and shirt material are purchased in the ratio of 2:3 by Jilli.
Let 2x m of trouser material and 3x m of shirt material be purchased by him.
Given that,
Cost price of the shirt per metre = ₹50 and Profit % = 12%
Cost price of the trouser per metre = ₹90 and Profit % = 10%
We know that,
Selling price = Cost Price + Profit
where, Profit = Profit% × Cost Price
Thus, per metre selling price of trouser material
= ₹ [90 + (90 × 10/100)]
= ₹99
Per metre selling price of shirt material
= ₹ [50 + (50 × 12/100)]
= ₹56
Since the total sales made is ₹36,660, we get
Total selling price of trousers + Total selling price of shirt = 36660
99 × (2x) + 56 × (3x) = 36660 [Since the number of trousers and shirts are 2x and 3x respectively]
198x + 168x = 36660
366x = 36660
x = 100 (approx.)
Thus, trouser material = 2x m
= (2 × 100) m
= 200 m
Therefore, the trouser material that Jilli bought was 200 m.
Hope it's helpful!