B. 1.6
Let the weight of the body be n kg
weight of protein in the skin = 16% of 1/10 × n
=16/100 × 1/10× n
=2x/125 kg
Therefore, the require percent is = 2x/125÷x (100)
= 2/125 × 100
=0.016 × 100
= 1.6
**hope it helps**
**Brainliest my answer**
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Answers & Comments
B. 1.6
Let the weight of the body be n kg
weight of protein in the skin = 16% of 1/10 × n
=16/100 × 1/10× n
=2x/125 kg
Therefore, the require percent is = 2x/125÷x (100)
= 2/125 × 100
=0.016 × 100
= 1.6
**hope it helps**
**Brainliest my answer**