If it factors with rational numbers, it factors with whole numbers. So try
(ax + b) and (ax-b) where a is 1 or 2
and b is 1, 2, 3 or 6.
To give you a start, if (x-1) is a factor, then putting x = 1 in the polynomial will give result zero. By my reckoning 2–1–8+1+6 is indeed zero, so (x-1) is a factor. Now use polynomial long division (or just fiddling about) to reduce the polynomial to (x-1) x a
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Answer:
What is a factor of
2x^4 - x^3 - 8x^2 + x + 6?
If it factors with rational numbers, it factors with whole numbers. So try
(ax + b) and (ax-b) where a is 1 or 2
and b is 1, 2, 3 or 6.
To give you a start, if (x-1) is a factor, then putting x = 1 in the polynomial will give result zero. By my reckoning 2–1–8+1+6 is indeed zero, so (x-1) is a factor. Now use polynomial long division (or just fiddling about) to reduce the polynomial to (x-1) x a
cubic polynomial. And keep going.
This stuff can be quite fun.
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