1) Two liters of gas is confined in a container under a pressure of 760mmHg. What would be the new volume of the pressure is increased to 1,520 mmHg? SAMPLE PROBLEM 2) A sample of H has a volume of 10 liters at a pressure of 1 atm (100KPa), If the pressure is raised to 2 atm, what would be the volume be? 3)A sample of oxygen gas at 3 atmospheres has a volume of 100 liters. When compressed, its volume is reduced to 73 liters. What is the pressure on the gas when the volume is 73 liters? OMAN 4) A sample gas has a volume of 4 liters at a pressure of 5atm (500kPa). If the pressure is lowered to 2atm (200kPa), what would the volume be?
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Answer:
1) Using the formula P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume respectively, we can solve for V2:
P1V1 = P2V2
(760 mmHg)(2 L) = (1,520 mmHg)V2
V2 = 1 L
Therefore, the new volume at a pressure of 1,520 mmHg would be 1 liter.
2) Using the same formula, we can rearrange it to solve for V2:
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (1 atm)(10 L)/(2 atm)
V2 = 5 L
Therefore, the new volume at a pressure of 2 atm would be 5 liters.
3) Once again, using the formula P1V1 = P2V2, we can solve for P2:
P1V1 = P2V2
(3 atm)(100 L) = P2(73 L)
P2 = 130.1 atm
Therefore, the pressure on the gas when the volume is 73 liters is 130.1 atmospheres.
4) Rearranging the formula P1V1 = P2V2 to solve for V2:
P1V1 = P2V2
V2 = (P1V1)/P2
V2 = (5 atm)(4 L)/(2 atm)
V2 = 10 L
Therefore, the new volume at a pressure of 2 atm would be 10 liters.
Explanation:
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