let the common variable of angles be x
hence angles are,
2x,5x,5x,6x

sum of angles of a quadrilateral is 360
hence,
2x+5x+5x+6x = 360
18x = 360

x = 20

greatest angle = 6x = 6 x 20 = 120

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Answer:

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150=3b(15−b)

⇒  50=b(15−b)

⇒  50=15b−b2

⇒  b2−15b+50=0

⇒  b2−10b−5b+50=0

⇒  b(b−10)−5(b−10)=0

⇒  (b−10)(b−5)=0

∴  b=5 or b=10

Putting both values of b in equation ( 1),

⇒  a=15−5 or a=15−10

∴  a=10 or a=5