Answer:

Given :-

• Rekhadidi deposited Rs 10000 of her savings in two separate banks at the same time. The rate of simple interest per annum of 6% in one bank and that of 7% in other bank after 2 years. She gets Rs 1280 in total as interest.

To Find :-

• What is the money she had deposited separately in each of two banks.

Formula Used :-

where,

• S.I = Simple Interest
• P = Principal
• r = Rate of Interest
• t = Time

Solution :-

Let, Rekhadidi deposited in 1st bank is Rs x

And, she deposited in 2nd bank is Rs (10000 - x)

Now,

Given :

• Principal (P) = Rs x
• Rate of Interest (r%) = 6%
• Time (t) = 2 years

By substituting the formula we get,

⇒ S.I =

➠ S.I =

Again

Given :

• Principal (P) = Rs (10000 - x)
• Rate of Interest (r%) = 7%
• Time (t) = 2 years

By substituting the formula we get,

↦ S.I =

↦ S.I =

➦ S.I =

Now, according to the question,

↪

↪

↪

By doing cross multiplication we get,

↪

↪

↪

↪ x =

➪ x = Rs 6000

Hence, the required money she deposited separately in each of two banks are,

✧ In 1st bank = Rs x = Rs 6000

✧ In second bank = Rs (10000 - x) = Rs (10000 - 6000) = Rs 4000

Rekhadidi deposited Rs 6000 in 1st bank and Rs 4000 in 2nd bank.

1) Rekhadidi deposited Rs 10,000 of her savings in two separate banks at the same time. The rate of simple interest per annum is of 6% in one bank and that of 7% in other bank, after 2yrs, if she gets 1280 in total as interest, then let us wrte by calculating, the money she bad deposited separately in each of two banks