1. number method. Balance the following oxidation-reduction equations using the ...

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jiyaangelalucyenpolm @jiyaangelalucyenpolm

September 2022 1 0 Report

1. number method. Balance the following oxidation-reduction equations using the oxidation number method
a. HNO3 + HI ------> NO + I2 + H20

b. H2S + HNO3-------> S + NO + H2O

c. Ag + HI -------> NO HNO3 -----> S NO H2SO4 -----> Ag2804 + + H20 + H20 SO2 + H2

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c2rusfriend

a. 2HNO3 + 6HI = 2NO + 3I2 + 4H2O

b. 3H2S + 2HNO3 = 3S + 2NO + 4H2O

c. Impossible Reaction

jiyaangelalucyenpolm pls. with process

c2rusfriend Alright, I'll edit it. Please wait a moment. ᥬ᭄

c2rusfriend somehow i cant edit it but ill post my progress here ;-;

c2rusfriend STEP 1. You need to determine LHS and RHS values first.

Elements - LHS - RHS
H - 2 - 2
N - 1 - 1
O - 3 - 2
I - 1 - 2

c2rusfriend STEP 2. From the data we get that H and N are balanced while O and I are not balanced.

c2rusfriend STEP 3. First, let us consider balancing the Oxygen molecule (O). To balance O we need to add 2 in front NO in RHS. Thus, the equation will be HNO3 + HI = 2NO + I2 + H2O.

c2rusfriend STEP 4. Update your data.

c2rusfriend Elements - LHS - RHS
H - 2 - 2
N - 1 - 2
O - 3 - 3
I - 1 - 2

c2rusfriend STEP 5. As we can see, N and I are still unbalanced. We will balance N first by adding a 2 in front of HNO3.

c2rusfriend further steps will be posted later, thank you for your patience!

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